Published: Sat, January 06, 2018
Sport | By Cameron Gross

Rob Gronkowski earns incentive with first-team All-Pro selection

Patriots tight end Rob Gronkowski had 5.5 million reasons to have a big year.

Gronkowski was named a first-team All-Pro, which was one of the criteria that earned him the maximum incentives ($5.5 million). According to Mike Reiss of ESPN, this allows triggered a $2.5 million incentive bonus. He previously unlocked $3 million based upon gaining more than 1,000 receiving yards. He finished the regular season playing 79.3 percent of the offensive snaps, missing one game because of injury and one for an National Football League suspension for his late hit on Buffalo Bills cornerback Tre'Davious White. He finished with 69 receptions for 1,084 yards and eight touchdowns but needed either 80 catches, or 1,200 yards or 14 touchdowns to lock in the final roster bonus.

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Gronk had some pretty tough competition for the position, with Travis Kelce of the Chiefs putting up a monster season and Zach Ertz of the Eagles having a very nice year as well. He has been able to show durability this season being healthy heading into the playoffs where he figures to be a major factor in the passing game. This is the third time that Brady has earned this honor, and it is the fourth time that Gronkowski has earned it. His three career 100-yard receiving games in the postseason that is tied for third all-time among tight ends behind Vernon Davis (four) and Keith Jackson (four).

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